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x^2+27x+176=36
We move all terms to the left:
x^2+27x+176-(36)=0
We add all the numbers together, and all the variables
x^2+27x+140=0
a = 1; b = 27; c = +140;
Δ = b2-4ac
Δ = 272-4·1·140
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-13}{2*1}=\frac{-40}{2} =-20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+13}{2*1}=\frac{-14}{2} =-7 $
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